Learn about Sawtooth Wave Generator to improve your skills and design your electronics projects yourself.
Where can I get Sawtooth Wave Generator Circuit Diagram with Explanation?
IndiaBIX provides you lots of fully solved Sawtooth Wave Generator circuit diagram with detailed explanation and working principles.
How to design a Sawtooth Wave Generator (electronic circuit)?
You can easily design the Sawtooth Wave Generator circuit by practicing the exercises given below. Here you can design and simulate your own electronic circuits with this Online Circuit Designer and Simulator.
This circuit is an oscillator that generates a sawtooth wave. It's basically the same circuit as the triangle wave oscillator, except that the resistor in series with the capacitor has been replaced by two resistors, each paired with a diode going in opposite directions. For the first half of the cycle, the capacitor charges through a 40k resistor, and for the other half, it quickly discharges through a 5k resistor. -- Credits:Mr. Paul Falstad.
I tried this circuit. Its not producing waveform. I tried with different values.
(Feb 20, 2011)
I tried the same circuit in multisim but the output is not coming may I know the reason?
(May 13, 2013)
How saw tooth wave works?
(Jan 30, 2014)
The sawtooth waves only real use is for sound synthesis. Hook the output up to an 8 ohm speaker and connect the speaker to ground to hear a pure unfiltered sawtooth wave.
(Jan 30, 2014)
I don't get it. It only starts oscillating after you disconnect the power. I need constant power. Well I guess its because nothing is drawing current to theres no where for the electricity in the wires to go.
(Mar 22, 2014)
What are the applications of the saw-tooth generator?
(Mar 28, 2014)
Thanks for the diagram. I drew up the circuit in Orcad Capture and was able to run it fine. I changed the capacitor to a smaller value to increase the frequency. I am trying to design a circuit that produces a sawtooth at about 110-120 Hz to mimic the fundamental frequency of a male speaker.
I used Capture to generate a Fourier transform of the signal, and thought that the energy drops off pretty quick for what I want. I'm messing with different component values to try to decrease the dropoff.
I changed the 5k for a 2k, and the upper 40k for 80k, resulting in an even steeper slope in the fast component of the waveform. The Fourier transform resulted in an even bigger drop between the fundamental and the second harmonic, but the amplitude at higher frequencies seems to persist.
(Oct 28, 2014)
I do not have waveform in the output! Why?
(Apr 29, 2015)
No voltage source input why?
(May 16, 2015)
Can somebody explain what types of AO are in the circuit and what power supply it needs?
(Jan 1, 2016)
I try it. And the circuit doesn't work. My output just jump on maximum voltage level.
I tried with different voltage dividers answer still doesn't work.
(Mar 13, 2016)
Multivibrator needs no input.
(Sep 19, 2016)
Works only with dual power supply op amps. If you have a single supply op amp you need to modify the positive input of second op amp (and maybe the negative input of first op amp as well).
Ekrem Kaya said:
(Nov 11, 2019)
I have tried with LM358 opamp with single power supply by adding virtual zero point. Worked well. Added another opamp and a pot to produce variable PWM signal.
(Jan 11, 2021)
Lots of people seem to be having problems with this circuit. I assure you that with sensible op amps and component values it works perfectly. For those that have tried and failed are you using a split supply for your op amp (ie +/- Vcc)? If you are using a single supply then the grounded inputs to the op amp need to be connected to a mid supply voltage, easily established by two 10K resistors.
Use an op amp with rail to rail output for maximum ramp voltage. For those that have asked for how the circuit works the RH op amp is an integrator. The LH op amp is a Schmitt trigger with hysteresis from the positive feed back to reset the integrator. The circuit is readily adjusted to alter both the ramp frequency, the ramp amplitude, and the ramp average voltage. Note that as drawn the 5K resistor and the diode connected to the 40K resistor are not actually required.
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.