Electronics and Communication Engineering - Signals and Systems - Discussion

Discussion Forum : Signals and Systems - Section 1 (Q.No. 4)
4.
Consider Pole zero diagram as shown, If two Poles are moved in opposite direction towards ω = p/2 and -p/2, the filter will be
change to high pass filter
change to Band Pass filter
remains same
change to LPF
Answer: Option
Explanation:

But still we will get the same response, zero are at same position.

Discussion:
13 comments Page 1 of 2.

Neha said:   10 years ago
If you consider x(z) = (z-1)(z+1)/z2.

Then if z = ejw = cosw + jsinw.

Then x(ejw) = (e2jw - 1)/e2jw.

Now magnitude is X(w) = ((Cos 2w-1)2 + (sin 2w)2) 1/2.

As magnitude = (Real 2+image 2) 1/2.

So the plot is given for its magnitude similarly when you change the poles there won't be change in magnitude, hence filter remains the same.

Hope you will understand this.

Bibo said:   9 years ago
For digital domain, in low frequency w = 0 hence z = exp(j0) = 1.
High-frequency w = pi, z = -1 now put z = 1 and -1 and find response, you will get zero every time.

Hence, both are Band Pass filter.

Kishore said:   8 years ago
In denominator how did z^2 came, poles should come in denominator and zeroes should come in the numerator. Explain me clearly.

Nabil said:   1 decade ago
I didn't understand the logic. Kindly provide me the detailed solution with proper reasoning.

Fatima noor said:   6 years ago
Zeros are same but poles are changed. Then How we get the same response?

Susee said:   1 decade ago
I cannot understood. Could you please explain me once?

Lavanya said:   7 years ago
I am not getting this, can anyone explain me in clear?

Geetha said:   6 years ago
I didn't understand, Please anyone, explain me.

Rachana said:   7 years ago
Thank you all for providing best explanation.

Neal said:   5 years ago
Not getting a clear solution. Anyone explain.


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