Electronics and Communication Engineering - Signals and Systems - Discussion
Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)
1.
What about the stability of system in 
Answer: Option
Explanation:
ROC include the unit circle hence it is stable.
Discussion:
49 comments Page 2 of 5.
Harshith said:
6 years ago
It is unstable when z>2.
Meena said:
7 years ago
I don't understand. Please explain in detail.
D.SIVASAMY said:
7 years ago
System is unstable because pole 2 locating outside the unit circle.
RAM said:
7 years ago
Can't understand please can anyone explain it?
Iram said:
7 years ago
H(z) = (-3/4z)/(z-0.4) + (16/5z)/(z-2) this is final transfer function. by sketching its ROC it can be seen that pole at 2 Roc lie outside unity circle while pole at 0.4 Roc includes unity circle by expanding in an outward direction.
So, the system is stable.
So, the system is stable.
Dhivya said:
7 years ago
Can anyone please explain how to solve these type of problem?
It's me . . . said:
7 years ago
System is stable.
For the system to be stable, the unit circle should lie between ROC.
Hence unit circle lie between 0.4 and 2.
For the system to be stable, the unit circle should lie between ROC.
Hence unit circle lie between 0.4 and 2.
Sk jha said:
8 years ago
I think the system is unstabe.
Sridevi said:
8 years ago
Please give the explanation of the answer clearly.
Zahoor said:
8 years ago
Since one pole magnitude lies outside the unit circle so system is unstable.
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