# Electronics and Communication Engineering - Signals and Systems - Discussion

Discussion Forum : Signals and Systems - Section 1 (Q.No. 1)

1.

What about the stability of system in

Answer: Option

Explanation:

ROC include the unit circle hence it is stable.

Discussion:

49 comments Page 5 of 5.
Arun Kumar Gupta said:
9 years ago

Without ROC one can't say that system is stable or not.

Shamsheer said:
10 years ago

ROC is |Z|>2 and .4<|Z|<4/3.

Why everyone are concerned with pole Z=2?

Why everyone are concerned with pole Z=2?

Manan said:
10 years ago

According to me system is unstable.

Shivanand jaiswal said:
10 years ago

roc of given problem z>2 and z>0.4 so intersection of this will be z>2 that is outside the unit circle tending to infinite this is an casual system but not stable.

Sathiya (ponds) said:
10 years ago

The pole Z=2 lies outside the unitcircle. The ROC is not mentioned in this question so the system is unstable.

Ajay kumar sharma said:
10 years ago

Pole doesn't lies b/w the circle so the system is not stable.

Raam said:
10 years ago

One of the pole z=2 lies outside the unit circle, so the system is unstable.

S.p.Bharath said:
10 years ago

The pole Z=2 lies outside the unity circle. Then how can we say it as stable ?

Iman said:
10 years ago

I think the ROC would have to be mentioned in the question to answer the question. Like 0.4 < |z| < 2.

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers