### Discussion :: Satellite Communication - Section 1 (Q.No.5)

Prakhar said: (Apr 1, 2014) | |

Antenna diameter is inversely proportional to the operating frequency. |

Nisha said: (May 29, 2014) | |

Lambda = c/f. If f' = 5f. Then lambda' = lemda/5 = height of antenna = 4m. |

Nirav Solanki said: (Jan 19, 2015) | |

Here frequency is multiplied by 5 means the wavelength is divided by 5. Now length of antenna is directly proportional to the half of the wavelength. So the ultimate length of antenna is divided by 5. |

Shreya said: (Feb 24, 2015) | |

20m antenna-----4/6GHZ-----multiply by 5. ?---------------20/30GHZ. 4*5/6*5-----20/5=4m. |

Anurag Nande said: (Apr 6, 2015) | |

Antenna diameter (d) is inversely proportional to the operating frequency (f). So d = k*(1/f). Note :- Here k is constant. For up link f = 4GHz for down link f = 6GHz. d = k*1/4 d = k*1/6. d/5 = k*1/(4*5). d/5 = k*1/(6*5). d/5 = k/20 ---(1) d/5 = k/30----(2). So the resultant size of antenna from equation (1) and (2): Size = d/5 = 20/5 = 4m. Size = 4m. |

Shivanirajput said: (Jun 18, 2015) | |

Antenna diameter is inversely proportional to frequency. So f*5 = d/5 = 4m. |

Zarana said: (Sep 17, 2015) | |

How put 5? We need height of 20/30 frequency. So do 4*5/6*5 & dived by 5 to 20 meter height? So answer is 4? |

Suresh said: (Nov 26, 2015) | |

Thanks to explaining all of these. |

Indu said: (Mar 17, 2016) | |

How put 5? |

Amul said: (Aug 13, 2016) | |

Thanks for the explanation. It's very easy to understand. |

Thanam Siva said: (Jan 2, 2018) | |

Thanks for explaining it. |

Vaishu said: (Jan 23, 2020) | |

How 5? |

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