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Electronics and Communication Engineering - Power Electronics - Discussion

Discussion Forum : Power Electronics - Section 1 (Q.No. 2)
Power Electronics
2.
In the below figure the average load current is 15 A. The rms value of transformer secondary current is
15 A
10.61 A
7.5 A
14.14 A
Answer: Option
Explanation:

RMS secondary current = = 15/1.414 = 10.608 A.

Discussion:
10 comments Page 1 of 1.
Abhishek said:   8 years ago
No, it's not correct.

As RMS value for full wave rectifier is = Imax/1.41.

And here Imax was not given, instead of it, Avg load current was given which is not same as Imax.

So, Irms is 1.11 * Iavg = 1.11* 15 = 16.65A.

Can anyone agree with me?
(4)
Pavi said:   11 months ago
Iav = (2*Im)/π.
Iav = 15A.
Im = (15 * π)/2 = 23.56.
Irms = Im/√2 = 23.56/√2 = 16.61 A.
(2)
Muruganandam said:   1 decade ago
How can the RMS will be lower than average?
PANDE said:   1 decade ago
How it can obtain?
Sachin said:   10 years ago
Please, elaborate the solution.
Priya said:   8 years ago
But this is thyristor not diode.
Lopamudra said:   8 years ago
Yeah, the thyristor is a controlled rectifier only. That means diode.
Kiran said:   5 years ago
Explain the correct answer.
Renjith V R said:   5 years ago
15 A is load current, So It will be the answer.
Priyanka said:   3 months ago
Root Mean Square (RMS) value of an alternating current (AC) , you typically use the formula: IRMS = I0 / √2, where I0 is the peak current (the maximum value of the current in one direction).

This formula applies specifically to sinusoidal AC waveforms.
So
Io is 15A,
IRMS = I0/√2,
IRMS = 15/1.414 = 10.608A.

So, the Answer is option B.
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