Electronics and Communication Engineering - Power Electronics - Discussion
Discussion Forum : Power Electronics - Section 1 (Q.No. 11)
11.
An SCR is triggered at 40° in the positive half cycle only. The average anode current is 50 A. If the firing angle is changed to 80°, the average anode current is likely to be
Answer: Option
Explanation:
.
Discussion:
5 comments Page 1 of 1.
Rupesh9292 said:
1 decade ago
Please justify.
Vamsi said:
9 years ago
Please explain it in clear.
Hanu said:
8 years ago
Explain it clearly.
Vivek yadav said:
8 years ago
i for 80/i for 40=0.66,
given i for 40 = 50,
then i for 80=50*0.66=33 A so option c is correct.
given i for 40 = 50,
then i for 80=50*0.66=33 A so option c is correct.
Jiaac said:
6 years ago
Since Vm is constant for the two cases, the ratio can be written as:
(1+cos40°)/(1+cos80°) = 50A/X.
Solve for X, and you get the average anode current of 33.23A for 80° firing angle.
Since 33.23A is less than 50A but more than 25A, option C is correct.
(1+cos40°)/(1+cos80°) = 50A/X.
Solve for X, and you get the average anode current of 33.23A for 80° firing angle.
Since 33.23A is less than 50A but more than 25A, option C is correct.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers