### Discussion :: Power Electronics - Section 1 (Q.No.11)

Rupesh9292 said: (May 19, 2015) | |

Please justify. |

Vamsi said: (Dec 5, 2016) | |

Please explain it in clear. |

Hanu said: (Feb 9, 2018) | |

Explain it clearly. |

Vivek Yadav said: (Feb 16, 2018) | |

i for 80/i for 40=0.66, given i for 40 = 50, then i for 80=50*0.66=33 A so option c is correct. |

Jiaac said: (Sep 19, 2019) | |

Since Vm is constant for the two cases, the ratio can be written as: (1+cos40°)/(1+cos80°) = 50A/X. Solve for X, and you get the average anode current of 33.23A for 80° firing angle. Since 33.23A is less than 50A but more than 25A, option C is correct. |

#### Post your comments here:

Name *:

Email : (optional)

» Your comments will be displayed only after manual approval.