Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 2 (Q.No. 15)
15.
The voltage e0 in the figure
Answer: Option
Explanation:
Apply mesh analysis in both the mesh by converting 8A current source into voltage source.
80 = 18 I1 - 6I2 + 16
1 - 12I2 - 6I2 + 6I1 = - 16
I1 = 4.3A, I2 = 2.3A
Hence e0 = 13I2 13 x 2.3 28 volts.
Discussion:
4 comments Page 1 of 1.
Anitha said:
5 years ago
Use nodal.
-8+(v1÷10)+(v1-v0÷2) = 0.
(V0-v1÷2)+(v0-16÷6)+(v0÷12) = 0.
-8+(v1÷10)+(v1-v0÷2) = 0.
(V0-v1÷2)+(v0-16÷6)+(v0÷12) = 0.
Feroz khan said:
7 years ago
Then what about the capacitor?
Hemant said:
9 years ago
And in second mesh equation from where did you take 1?
Mahesh said:
10 years ago
You are type wrong number at last stage, its 12 instead of 13.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers