Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 3 (Q.No. 20)
20.
In figure, E = 1 V (rms value). The average power is 250 mW. Then phase angle between E and I is
Answer: Option
Explanation:
EI cos θ = 0.25 or I cos θ = 0.25
From above equations cos θ = 0.707 and θ = 45°.
Discussion:
4 comments Page 1 of 1.
LOHITH said:
1 decade ago
How can you say like Z cos θ = 2?
Skm said:
8 years ago
Here, R=Zcosθ.
Ravi said:
8 years ago
What will be answer 60° or 45°?
(1)
Dipti swaroop said:
8 years ago
We know Z = zcosθ + isinθ , here zcosθ is real term i.e. 2 and isinθ is imaginary term.
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