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Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 10 (Q.No. 16)
Networks Analysis and Synthesis
16.
In figure the open circuit emf is
15 V
1.45 V
1.475 V
1.485 V
Answer: Option
Explanation:

Since emfs of two cells are not equal, a circulating current flows.

.

OC emf = 1.5 - (0.25)(0.1) = 1.475 V.

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