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Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 1 (Q.No. 17)
Networks Analysis and Synthesis
17.
A capacitor stores 0.15C at 5 V. Its capacitance is
0.75 F
0.75 μF
0.03 F
0.03 μF
Answer: Option
Explanation:

Q = CV or 0.15 = C(5) or C = 0.03 F.

Discussion:
4 comments Page 1 of 1.
Nuzi said:   7 years ago
Q=cv. So. C=q/v.

Here. Q=0.15, v=5.
C=0.15/5,
=0.03.
Arjun said:   8 years ago
A is the correct option.
Tamil said:   8 years ago
Q=CV. Q=0.15*5 =0.75F.

So, Option A is correct.
TULASIRAM said:   8 years ago
Not 0.03, it is only 0.3F.
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