Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 3 (Q.No. 1)
1.
In figure, the value of R should be
Answer: Option
Explanation:
The resistance of parallel combination = 
Discussion:
7 comments Page 1 of 1.
Akashbsk said:
3 years ago
1/R(parallel) = 1/R + 1/15 + 1/15.
R (parallel) = 15R/15 + 2R
R = V/R
10 + 15R/15 + 2R = 40/3,
R = 6 Ohm.
R (parallel) = 15R/15 + 2R
R = V/R
10 + 15R/15 + 2R = 40/3,
R = 6 Ohm.
(1)
Ram said:
7 years ago
How to get 1/12 here?
Shivu said:
6 years ago
Yes, how to get 1/12?
Rexi said:
6 years ago
1/R, instead of 1/12.
Nvk said:
6 years ago
Give proper explanation.
Jayanta said:
6 years ago
It should be 4.23 Ω.
Kuns said:
5 years ago
Parallel resistor = 15R/15 + 2R.
Series with 10ohm = 10 + 15R/15 + 2R.
R = V/I.
10 + 15R/15 + 2R = 40/3.
R = 6ohm.
Series with 10ohm = 10 + 15R/15 + 2R.
R = V/I.
10 + 15R/15 + 2R = 40/3.
R = 6ohm.
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