Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion

Discussion Forum : Networks Analysis and Synthesis - Section 3 (Q.No. 1)
1.
In figure, the value of R should be
12 Ω
6 Ω
3 Ω
1.5 Ω
Answer: Option
Explanation:

The resistance of parallel combination =

Discussion:
7 comments Page 1 of 1.

Akashbsk said:   3 years ago
1/R(parallel) = 1/R + 1/15 + 1/15.
R (parallel) = 15R/15 + 2R
R = V/R
10 + 15R/15 + 2R = 40/3,
R = 6 Ohm.
(1)

Kuns said:   5 years ago
Parallel resistor = 15R/15 + 2R.
Series with 10ohm = 10 + 15R/15 + 2R.
R = V/I.
10 + 15R/15 + 2R = 40/3.
R = 6ohm.

Jayanta said:   6 years ago
It should be 4.23 Ω.

Nvk said:   6 years ago
Give proper explanation.

Rexi said:   6 years ago
1/R, instead of 1/12.

Shivu said:   6 years ago
Yes, how to get 1/12?

Ram said:   7 years ago
How to get 1/12 here?

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