Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 1 (Q.No. 37)
37.
The electrical energy required to heat a bucket of water to a certain temperature is 2 kWh. If heat losses, are 25%, the energy input is
Answer: Option
Explanation:
Since 25% of input is lost, 0.75 Input = 2 or input = 
Discussion:
5 comments Page 1 of 1.
Trups said:
9 years ago
How 0.75 came?
Annasab said:
9 years ago
Let total applied energy is x.
Then,
x = 2k + 25% of x.
By solving x = 2.67.
Then,
x = 2k + 25% of x.
By solving x = 2.67.
Panda said:
8 years ago
Let total energy is x.
According to the question,
X - 20x/100 = 4kwh.
X-x/5 = 4,
5x-x/5 = 4,
4x = 20,
X = 5kwh.
Am I correct?
According to the question,
X - 20x/100 = 4kwh.
X-x/5 = 4,
5x-x/5 = 4,
4x = 20,
X = 5kwh.
Am I correct?
Aidi said:
8 years ago
100-25 = 75.
75/100 = 0.75.
75/100 = 0.75.
Zulu said:
6 years ago
If input energy is E.
Then;
Input energy (E) - 25/100 of energy loss= 2kw.
E(1-0.25) = 2kw.
E = 2/0.75 =2.67kw.
Then;
Input energy (E) - 25/100 of energy loss= 2kw.
E(1-0.25) = 2kw.
E = 2/0.75 =2.67kw.
(1)
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