Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
46.
One commercial unit of energy is equal to
Answer: Option
Explanation:
Consumers are charged on the basis of kWh of energy used.
47.
In figure which is correct at any time t
Answer: Option
Explanation:
As per KCL sum of currents entering a node is equal to sum of currents leaving the node.
48.
Two coupled coils with self inductances of 4 mH and 16 mH are connected in series. The maximum possible value of inductance can be
Answer: Option
Explanation:
Inductance = 4 + 16 + 24 x 16 = 36 mH.
49.
In using KCL it is necessary that current leaving a node is written as negative.
Answer: Option
Explanation:
It may be written as positive or negative as per convenience.
50.
A resistor is rated at 0.75 watt, 1 kΩ. Its current rating is
Answer: Option
Explanation:
0.75 = I2 x 1 x 1000 or I = 27.386 mA.
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