Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
41.
In active filters inductances are divided because they
Answer: Option
Explanation:
Active filters consist of electronic components and have very small size.
42.
Three resistance of 15 Ω each are connected in delta. The resistance of equivalent star will have a value of
Answer: Option
Explanation:
43.
The circuit in figure(1) is replaced by that in figure(2). It remains same R0 will be
Answer: Option
Explanation:
Net resistance of circuit is 4.571 R and that of circuit is 0.571 R.
Hence R0 be 4R.
44.
In a varistor the v-i graph is linear.
Answer: Option
Explanation:
The v-i graph, in varistor, is non-linear.
45.
In the circuit of figure the current through 5 Ω resistance at t = 0+ is
Answer: Option
Explanation:
Since 3 ohm resistance is short-circuited by capacitor, I = 20/5 A.
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers