Electronics and Communication Engineering - Microwave Communication - Discussion
Discussion Forum : Microwave Communication - Section 4 (Q.No. 22)
22.
A TE10 rectangular waveguide is to be designed for operation over 25-35 GHz and the band centre is 1.5 times the cutoff frequency. The dimension of broadside is
Discussion:
4 comments Page 1 of 1.
Prabhav agarwal said:
9 years ago
How to solve this question? Please assist me.
Priyanka said:
8 years ago
Please help to solve this problem.
Rozalind said:
6 years ago
What I come up with, c/(35Ghz-25Ghz).
Then divide it by 2 since a=wavelength/2,
Then multiply by 1.5 and I got 7.5mm.
Then divide it by 2 since a=wavelength/2,
Then multiply by 1.5 and I got 7.5mm.
Jen said:
3 years ago
Center frequency is 30 GHz, and it is 1.5 of f cutoff thus;
20GHz = c/2a,
a = 7.5mm.
20GHz = c/2a,
a = 7.5mm.
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