Electronics and Communication Engineering - Microprocessors - Discussion

Discussion Forum : Microprocessors - Section 1 (Q.No. 10)

Microprocessors

10.

When .4546 E 5 and .5433 E 7 are to be added in normalized floating point mode

none of the numbers is changed to any other form

.4546 E 5 is changed .004546 E 7 and .5433 E 7 is not changed

.5433 E 7 is changed to 54.33 E 5 and .4546 E 5 is not changed

both the numbers are changed and their exponents are made equal to 6

Answer: Option

Explanation:

Exponents are made equal and integer part is made zero.

Discussion:

22 comments Page 2 of 3.

Ashwiniya said: 9 years ago

I don't understand can you please explain me?

Prathyu said: 9 years ago

Please give me the explanation for this question. Why we change only the 1st number?

Akshay said: 8 years ago

The number 43.76 x 106 is represented in this notation as 04376 E 8, where E 8 is used auto represent 108.

The it is .4376 and the exponent is 8.

(1)

Ahmed jwad said: 7 years ago

Please explain floating point number addition method.

Abhishek said: 7 years ago

@Akshay.

Can you explain in detail, please?

Sanjeev said: 7 years ago

How can we decide exponent is 8 for that number?

Not understand please explain in detail sir.

Vennela sireesha said: 6 years ago

I am not understanding it, please explain briefly.

Ruksana said: 5 years ago

E 5 is equivalent to 10^5.

Aryadip Mridha said: 5 years ago

I didn't understand the problem, can anyone help me?

Jeshnavi said: 4 years ago

@Akshay.

Then what about E5 & E7.

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