Electronics and Communication Engineering - Microprocessors - Discussion
Discussion Forum : Microprocessors - Section 1 (Q.No. 10)
10.
When .4546 E 5 and .5433 E 7 are to be added in normalized floating point mode
Answer: Option
Explanation:
Exponents are made equal and integer part is made zero.
Discussion:
22 comments Page 1 of 3.
Dafwertgwth said:
2 years ago
.4546e5 = .4546*10^5
And .5433e7=.5433*10^7.
To make it equal we add 2 zeros to the first one to make powers equal i.e., .004546e7
Finally, only one option is satisfied.
And .5433e7=.5433*10^7.
To make it equal we add 2 zeros to the first one to make powers equal i.e., .004546e7
Finally, only one option is satisfied.
Manju said:
3 years ago
Please explain in detail.
Jeshnavi said:
4 years ago
@Akshay.
Then what about E5 & E7.
Then what about E5 & E7.
Aryadip Mridha said:
5 years ago
I didn't understand the problem, can anyone help me?
Ruksana said:
5 years ago
E 5 is equivalent to 10^5.
Vennela sireesha said:
6 years ago
I am not understanding it, please explain briefly.
Sanjeev said:
7 years ago
How can we decide exponent is 8 for that number?
Not understand please explain in detail sir.
Not understand please explain in detail sir.
Abhishek said:
7 years ago
@Akshay.
Can you explain in detail, please?
Can you explain in detail, please?
Ahmed jwad said:
7 years ago
Please explain floating point number addition method.
Akshay said:
8 years ago
The number 43.76 x 106 is represented in this notation as 04376 E 8, where E 8 is used auto represent 108.
The it is .4376 and the exponent is 8.
The it is .4376 and the exponent is 8.
(1)
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