Electronics and Communication Engineering - Measurements and Instrumentation - Discussion

Discussion Forum : Measurements and Instrumentation - Section 1 (Q.No. 31)
31.
A full wave rectifier type meter is used to measure the wave shape shown in figure. The voltmeter is calibrated to read rms value of sine wave. The reading of voltmeter will be
100 V
111 V
Answer: Option
Explanation:

Peak value of sine wave = 100 x 1.11 = 111 V.

Discussion:
11 comments Page 1 of 2.

Mintokz said:   9 years ago
After rectifier, the voltage is a DC of value 100V. Would why its peak to be detected?

The RMS value of the dc same as its voltage (Being DC) and the meter reads RMS value itself. So, the answer will be 100V.

Ppn said:   9 years ago
I agree with Mintokz, The peak value is 100.

Saad said:   9 years ago
From where did you got 1.11?

Shinu said:   9 years ago
I think the wave shape is supposed to be a sine wave, not square.

Ajay said:   9 years ago
"The voltmeter is calibrated to read rms value of sine wave".

Why it is reading peak value?

Sreelekshmi said:   9 years ago
I think RMS value is for sine.

Ullas S S said:   9 years ago
As the given signal is different from regular sign wave , to get the RMS value we should multiply 1.11 to peak voltage.

Yurekha said:   9 years ago
Peak value= RMS * 1.414(value to be multiplied in case of the sine wave).
100 = RMS * 1.414
RMS = 100/1.414 i.e. 100/√2.
Then, How we get 1.11?

R.paul said:   9 years ago
1.11 is "form factor".

Ravi shanakar meena said:   8 years ago
RMS=FF*Avg.

As this instrument is calibrated for sine wave
Therefore it uses FF=1.11( BY DEFAULT full bridge rectifier)
and this square wave is fed to FWR, therefore the output will have the Avg of 100V.

so,RMS=1.11*100=111.


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