Electronics and Communication Engineering - Measurements and Instrumentation - Discussion
Discussion Forum : Measurements and Instrumentation - Section 2 (Q.No. 16)
16.
The power input and output in a device are 3650 W and 3385 W with each reading in doubt by ± 10 W. The percentage uncertainty in losses is
Answer: Option
Explanation:
Losses = 3650 - 3385 = 265 W uncertainty = ± 20 W.
.
Discussion:
5 comments Page 1 of 1.
Sagar said:
9 years ago
The answer is B because the uncertainty is 10 w.
Sai said:
9 years ago
Yes, the answer is B.
Jai said:
8 years ago
B is correct I think.
RINKU MEENA said:
7 years ago
The answer should be option B.
Kasavayya said:
7 years ago
Coming to power, uncertainty becomes double. So 2 * 10 = 20.
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