Electronics and Communication Engineering - Measurements and Instrumentation - Discussion

Discussion Forum : Measurements and Instrumentation - Section 2 (Q.No. 16)
16.
The power input and output in a device are 3650 W and 3385 W with each reading in doubt by ± 10 W. The percentage uncertainty in losses is
± 7.55%
± 3.77%
± 11.32%
± 15.09%
Answer: Option
Explanation:

Losses = 3650 - 3385 = 265 W uncertainty = ± 20 W.

.

Discussion:
5 comments Page 1 of 1.

Kasavayya said:   7 years ago
Coming to power, uncertainty becomes double. So 2 * 10 = 20.

RINKU MEENA said:   7 years ago
The answer should be option B.

Jai said:   8 years ago
B is correct I think.

Sai said:   9 years ago
Yes, the answer is B.

Sagar said:   9 years ago
The answer is B because the uncertainty is 10 w.

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