Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 11 (Q.No. 38)
38.
A MOD - 2 counter, the FF has a tpd = 60 nsec. The NOR gate has a tpd of 30 nsec. The clock frequency is
37 MHz
40 MHz
111 MHz
none
Answer: Option
Explanation:

Clock period should be greater than or equal tpd

MOD-12 → X FF = 4 x 60 = 240 n sec

tpd of NOR gate = 30 n sec Total = 240 + 30 ⇒ 270 n sec

.

Discussion:
Be the first person to comment on this question !

Post your comments here:

Your comments will be displayed after verification.