Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 21 (Q.No. 3)
3.
The input to a binary communication system, denoted by a random variable x, takes on one of the two values 0 or 1 with probabilities
and
. The behaviour of the communication system is modelled by
P(Y = 1 |x = 1|) =
and P(Y = 0|x = 0) = 
Find P(Y = 1)


P(Y = 1 |x = 1|) =


Find P(Y = 1)
Discussion:
1 comments Page 1 of 1.
Vishwamber kale said:
1 decade ago
P(Y = 1 |x = 1|) = 0.75 and P(Y = 1|x = 0) = 1/8,
p(x =0) = 0.75 p(x=1) = 0.25,
p( y=1) = P(Y = 1|x = 1|) *p(x=1)+P(Y = 1|x = 0)*p(x =0),
= 0.75*0.25+1/8 *0.75.
= 9/32.
p(x =0) = 0.75 p(x=1) = 0.25,
p( y=1) = P(Y = 1|x = 1|) *p(x=1)+P(Y = 1|x = 0)*p(x =0),
= 0.75*0.25+1/8 *0.75.
= 9/32.
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