# Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 21 (Q.No. 3)

3.

The input to a binary communication system, denoted by a random variable

P(Y = 1 |

Find P(Y = 1)

*x*, takes on one of the two values 0 or 1 with probabilities and . The behaviour of the communication system is modelled byP(Y = 1 |

*x*= 1|) = and P(Y = 0|x = 0) =Find P(Y = 1)

Discussion:

1 comments Page 1 of 1.
Vishwamber kale said:
10 years ago

P(Y = 1 |x = 1|) = 0.75 and P(Y = 1|x = 0) = 1/8,

p(x =0) = 0.75 p(x=1) = 0.25,

p( y=1) = P(Y = 1|x = 1|) *p(x=1)+P(Y = 1|x = 0)*p(x =0),

= 0.75*0.25+1/8 *0.75.

= 9/32.

p(x =0) = 0.75 p(x=1) = 0.25,

p( y=1) = P(Y = 1|x = 1|) *p(x=1)+P(Y = 1|x = 0)*p(x =0),

= 0.75*0.25+1/8 *0.75.

= 9/32.

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