Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 3 (Q.No. 32)
32.
In the following limiter circuit, an input voltage V1 = 10 sin 100pt applied. Assume that the diode drop is 0.7 V when it is forward biased. The zener breakdown voltage is 6.8 V

The maximum and minimum values of the output voltage respectively are

The maximum and minimum values of the output voltage respectively are
Answer: Option
Explanation:
During +ve part of Vi
D1 will be forward biased
Zener diode is reverse biased
Thus net voltage = 6.8 + 0.7 = 4.5 V
During -ve part of Vi
D2 will be forward biased
D1 will be reversed biased
Thus net voltage = -0.7 V .
Discussion:
1 comments Page 1 of 1.
Shashank said:
3 years ago
Net voltage in +ve has been mistyped to 4.5 instead of 7.5.
please correct it.
please correct it.
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