Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 2 (Q.No. 25)
25.
For real values of x, the minimum value of the function f(x) exp (x) + exp (- x) is
Answer: Option
Explanation:
f(x) = ex + e-x
f(x) = ex - ex
f(x) = 0 ⇒ ex - e-x = 0
f'(x) = ex + e-x ⇒ +ve for x = 0
Thus minimum.
Minimum f(x) = e0 + e0 = 2.
Discussion:
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