Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 11 (Q.No. 44)
44.
For the network shown, determine z1 , z0 and Av
zi = 1.067 Ω; z0 = 3 kΩ; Av = 280
zi = 1.067 Ω; z0 = 3 kΩ; Av = - 280.37
zi = 937 Ω; z0 = 3 Ω; Av = 281
zi = 937 Ω; z0 = 33 kΩ; Av = - 280.37
Answer: Option
Explanation:

= 24.04 μA

IE = (1 + β)IB = 2.428 mA;

= 10.7 Ω

(i) zi = RB||Bre =

= 0.937 K = 1.067 K

(ii) Z0 = RC = 3 kΩ

(iii) = -280.37

Zi = 1.067 KΩ;

Z0 = 3 KΩ;

Av = -280.37 .

Discussion:
Be the first person to comment on this question !

Post your comments here:

Your comments will be displayed after verification.