Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 12 (Q.No. 16)
16.
VL = 100 cos (10t + 30°)
R = 10 Ω XL = j10 Ω
XC = - j4 Ω

Find Vs
116.57 sin (10t - 29°) V
116.57 sin (10t + 29°) V
117.00 sin (10t - 29°) V
117.00 sin (10t + 29°) V
Answer: Option
Explanation:

VC = XC X I = 7.07 X 4∠ -90° - 60° = 28.28∠ - 150°V

VR = I X R = 7.07 ∠-60° x 10 = 70.7∠ - 60°

Vs = 70.7∠30° + 70.7∠-60° + 28.28∠-150° = 82.44∠-29° V

vs = 116.57 sin (10t - 29°) V.

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