Electronics and Communication Engineering - Exam Questions Papers - Discussion

Discussion Forum : Exam Questions Papers - Exam Paper 1 (Q.No. 18)

Exam Questions Papers

18.

What are the values of E_max and E_min displayed on the oscilloscope, when a 1 kV P-P carries is modulated to 50%?

2 kV, 0.5 kV

1 kV, 0.5 kV

0.75 kV, 0.25 kV

0.5 kV, 1.5 kV

Answer: Option

Explanation:

E_max - E_min = 0.5 x 1 kV = 0.5 kV

2E_max = 1.5 kVi, E_max = 0.75 kV

E_min = 0.25 kV.

Discussion:

1 comments Page 1 of 1.

Nor said: 2 years ago

Can someone explain it further to understand?

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