Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 5 (Q.No. 42)
42.
A point charge of 6 μC is located at the origin, uniform line charge density of 180 nC/m of 8 m length lies along the x axis and a uniform sheet of charge equal to 25 nC/m2 of area p x 42 lies in the z = 0 plane. Calculate total electric flux leaving the surface of sphere of 4 m radius centered at origin.
Answer: Option
Explanation:
According to Gauss's law total flux leaving the closed surface is equal to the charge enclosed by the closed surface
Qencl = (6 x 10-6) + (8 x 180 x 10-6) + (p x 42 x 25 x 10-9)
= (6 x 10-6) + (1.44 x 10-6) + (1.257 x 10-6)
= 8.697 μ Coulombs.
Discussion:
2 comments Page 1 of 1.
Sunil said:
8 years ago
What is the formula for this?
Sunil said:
8 years ago
Why 180*10^-6 is used?
Instead of 10^-9.
Instead of 10^-9.
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