Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 12 (Q.No. 21)
21.
A sample of N-type semiconductor has electron density of 6.25 x 1018/cm3 at 300k. If the intrinsic concentration of carriers in this sample is 2.5 x 1013/cm3 at this temperature the hole density works out to be
Discussion:
2 comments Page 1 of 1.
Bebemo said:
6 years ago
Ni^2 = Ne*Np.
Np = Ni^2 / Ne,
Np = (2.5x10^13)^2 / 6.25x10^18,
Np = 10^8.
Np = Ni^2 / Ne,
Np = (2.5x10^13)^2 / 6.25x10^18,
Np = 10^8.
Avinash said:
6 years ago
Please explain the answer.
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