Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion

Discussion Forum : Electronic Devices and Circuits - Section 1 (Q.No. 22)
22.
An amplifier without feedback has a voltage gain of 50, input resistance of 1 kΩ and output resistance of 2.5 kΩ. The input resistance of the current shunt -ve feedback amplifier using the above amplifier with a feedback factor of 0.2 is
1/11 kΩ
1/5 kΩ
5 kW
11 kW
Answer: Option
Explanation:

Input Resistance with feedback for current shunt, .

Discussion:
11 comments Page 1 of 2.

Kartikey said:   3 years ago
1/11 is wrong answer, because in question voltage gain is given but there is a mixing of current so first we have.

To calculate current gain then we will use formula A/1+BA.

Thankyou!
(1)

Aravind said:   5 years ago
I agree. Thanks. @Sri Abhijit.

Sri Abhijit said:   5 years ago
1/11 is correct.

Because the formula is Ri/1+(alpha*beta),
So it will be 1/1+(50*0.2)= 1/11.
(1)

Sanjay said:   5 years ago
What about shunt series?

Gourab said:   6 years ago
What is 2.5kohm here? please elaborate.

Janhavi said:   7 years ago
@Ram Prasad.

Please, can you elaborate it.

Katekyo said:   8 years ago
Just remember that current shunt is shunt-shunt and when it's shunt, the R values reduce, so just divide R-value with the " sacrifice factor" (1+AB).

In this case, original Ri=1k, since its shunt in the input, just divide 1k by (1+50*0.2) = 1/11 kohms.

Prem Kumar said:   9 years ago
I agree @Ram Prasad.

The answer should be 1/5.
(1)

Ajit said:   9 years ago
Ri' = Ri (1 + Aβ),
Ri' = 1 K (1 + 59 * 0.2),
Ri' = 11 K.

Vishaldeep said:   1 decade ago
RI(with feedback) = RI/(1+βA) = 1/(1+[50*0.2]) = 1/11.

Voltage gain is considered.


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