Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
36.
A pulse train with a 1 MHz frequency is counted using a 1024 modulus ripple counter using JK flip flops. The maximum propagation delay for each flip-flop should be
Answer: Option
Explanation:
Total delay = = 1 ms = 10 x delay of one flip flop. Therefore delay for one flip-flop = 0.1 ms.
37.
What will be maximum input that can be converted for a 6 bit dual slope A/D converter uses a reference of -6v and a 1 MHz clock. It uses a fixed count of 40 (101000).
Answer: Option
Explanation:
.
38.
In the given figure shows a logic circuit. The minimum Boolean expression for this circuit is


Answer: Option
Explanation:
Output A(B + C) + AB + C(A + B) = AB + AC + AB + AC + BC = B + A + BC = A + B + C.
39.
If number of information bits is 11, the number of parity bits in Hamming code is
Answer: Option
Explanation:
2p > m + p + 1. If m = 11, p must be 4 to satisfy this equation.
40.
The number of digit 1 present in the binary representation of 3 x 512 + 7 x 64 + 5 x 8 + 3 is
Answer: Option
Explanation:
3 x 512 + 7 x 64 + 5 x 8 + 3
= (2 + 1) x 29 + (4 + 2 + 1)26 + (4 + 1)23 + (2 + 1)
= 210 + 29 + 28 + 27 + 26 + 25 + 23 + 21 + 1
= 210 + 29 + 28 + 27 + 26 + 25 + 23 + 21 + 20
9 term of power two
Hence number of '1' is 9.
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