Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
21.
Assertion (A): Master slave JK flip flop is commonly used in high speed synchronous circuitry
Reason (R): Master slave JK flip flop uses two JK flip flops in cascade.
Answer: Option
Explanation:
R-S, J-K flip-flop is not used very commonly.
22.
Inputs A and B of the given figure are applied to a NAND gate. The output is LOW


Answer: Option
Explanation:
NAND gate gives Low output if all inputs are High. For other combinations of inputs, output is High.
23.
ECL is a saturating logic.
Answer: Option
Explanation:
It is a non-saturating logic. Hence highest speed of operation.
24.
For the NMOS gate in the given figure, F =


Answer: Option
Explanation:
B + C are in parallel and A is in series with this parallel combination, Similarly D + E are in series. Then D, E are in parallel with A, B and C Y = A(B + C) + DE .
25.
The resolution of 4 bit counting ADC is 0.5 volt, for an Analog input of 6.6 volts. The digital output of ADC will be
Answer: Option
Explanation:
Digital output of ADC resolution = .
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