Electronics and Communication Engineering - Electronic Devices and Circuits
Exercise : Electronic Devices and Circuits - Section 2
- Electronic Devices and Circuits - Section 13
- Electronic Devices and Circuits - Section 24
- Electronic Devices and Circuits - Section 23
- Electronic Devices and Circuits - Section 22
- Electronic Devices and Circuits - Section 21
- Electronic Devices and Circuits - Section 20
- Electronic Devices and Circuits - Section 19
- Electronic Devices and Circuits - Section 18
- Electronic Devices and Circuits - Section 17
- Electronic Devices and Circuits - Section 16
- Electronic Devices and Circuits - Section 15
- Electronic Devices and Circuits - Section 14
- Electronic Devices and Circuits - Section 1
- Electronic Devices and Circuits - Section 12
- Electronic Devices and Circuits - Section 11
- Electronic Devices and Circuits - Section 10
- Electronic Devices and Circuits - Section 9
- Electronic Devices and Circuits - Section 8
- Electronic Devices and Circuits - Section 7
- Electronic Devices and Circuits - Section 6
- Electronic Devices and Circuits - Section 5
- Electronic Devices and Circuits - Section 4
- Electronic Devices and Circuits - Section 3
- Electronic Devices and Circuits - Section 2
26.
The Boolean expression A ⊕ B is equivalent to
Answer: Option
Explanation:
A ⊕ B = AB + AB
27.
Which of these are two state devices?
Answer: Option
Explanation:
Each has 2 states.
28.
What will be minimum conversion rate in 6 bit dual slope A/D converter uses a reference of -6v and a 1 MHz clock. It uses a fixed count of 40 (101000).
Answer: Option
Explanation:
Minimum conversion rate 
.
29.
The minimum number of NAND gates required to implement the Boolean function A +AB + ABC is equal to
Answer: Option
Explanation:
A + AB +A B C = A + AB ( 1 + C) = A + AB = A(1 + B) = A.
30.
For the K map of the given figure, the simplified Boolean expression is
Answer: Option
Explanation:
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