Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 2 (Q.No. 28)
28.
What will be minimum conversion rate in 6 bit dual slope A/D converter uses a reference of -6v and a 1 MHz clock. It uses a fixed count of 40 (101000).
Answer: Option
Explanation:
Minimum conversion rate 
.
Discussion:
11 comments Page 1 of 2.
Manist said:
3 years ago
Here, for dual slop ADC ==>
Tc = 2^(n+1)/clock rate.
So, tc = 2^7/1MHz = 128 x 10^-6 Sec.
Tc = 2^(n+1)/clock rate.
So, tc = 2^7/1MHz = 128 x 10^-6 Sec.
(1)
CRMA said:
3 years ago
How? I am not getting it. Please explain me.
Thanks in advance.
Thanks in advance.
Shabarna said:
6 years ago
Please explain how 108 comes?
Lilian said:
6 years ago
What is the clock rate?
Dhanya said:
7 years ago
Please explain it more clearly.
LOHITHA DM said:
7 years ago
First find conversion time then go for conversion rate and then find tc then the conversion rate
Tc= 2^n/ clock rate.
Rate =1/tc.
Tc= 2^n/ clock rate.
Rate =1/tc.
(1)
Dhrubajyoti said:
8 years ago
How 108 comes?
Please explain.
Please explain.
Sonu kumar said:
9 years ago
What is 108?
Please explain clearly.
Please explain clearly.
Pritesh said:
9 years ago
What is this 108?
SHALINI said:
9 years ago
Please provide solution for this.
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