Electronics and Communication Engineering - Electromagnetic Field Theory - Discussion

Discussion Forum : Electromagnetic Field Theory - Section 1 (Q.No. 2)
2.
A broadside array consisting of 200 cm wavelength with 10 half-wave dipole spacing 10 cm. And if each array element feeding with 1 amp. current and operating at same frequency then find the half power beamwidth
10°
15°
Answer: Option
Explanation:

.

Discussion:
9 comments Page 1 of 1.

Boi said:   3 years ago
Explain what units are used?

Yash said:   4 years ago
What are HPBW and BWFN?

Abhi said:   4 years ago
HPBW=200/10*10=200/100=2°.
(2)

Rohit kumar said:   5 years ago
Beam Width Between First Nulls (BWFN).

Selca said:   7 years ago
d =λ divide by what?

Prithwiraj said:   7 years ago
I do not get it, someone please explain it.

Ravneet said:   7 years ago
This should be 2 radians not degrees.

Ragini said:   7 years ago
n is number of dipole.

Deepika Dhabhade said:   8 years ago
Why n value is taken as 20?

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