Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 19)
19.
Decimal 43 in hexadecimal and BCD number system is respectively.
Answer: Option
Explanation:
(43)10 = (2B)16
(43)10 = (01000011)2 .
Discussion:
17 comments Page 1 of 2.
Rathi said:
1 decade ago
In a binary system all possible combinations of bits are valid.
In a BCD system there are 4 bits per digit. And the only valid combinations are 0(0000 Binary) through to 9(1001 Binary). If you want more digits then you have to add another 4-bit set.
So the number 43 would be represented by 101011 in binary and 0100 0011 in BCD.
In a BCD system there are 4 bits per digit. And the only valid combinations are 0(0000 Binary) through to 9(1001 Binary). If you want more digits then you have to add another 4-bit set.
So the number 43 would be represented by 101011 in binary and 0100 0011 in BCD.
(1)
Lemlem Aragaw said:
6 years ago
43/16 =2.
16*2 =32.
therefore 43-32 =11.
Then we will convert 43 to binary number.
43/2 = 21 rem 1 again divide 21 with 2.
21/2 = 10 rem 1.
10/2 = 5 rem 0.
5/2 = 2 rem 1.
2/2 = 1 rem 0.
0101011.
so A=10.
B=11.
And the answer will be 2B, 0101011.
16*2 =32.
therefore 43-32 =11.
Then we will convert 43 to binary number.
43/2 = 21 rem 1 again divide 21 with 2.
21/2 = 10 rem 1.
10/2 = 5 rem 0.
5/2 = 2 rem 1.
2/2 = 1 rem 0.
0101011.
so A=10.
B=11.
And the answer will be 2B, 0101011.
(1)
Nagaraj said:
7 years ago
In hexa the given decimal number should be divided by 16 (in 43 it has 2 as a quotient) and the remainder should be converted to direct Hexa equivalent number (in here it is 11 it's equivalent hexa number is B).
So, combining these we get {2B}.
So, combining these we get {2B}.
Arora rox said:
1 decade ago
For hexadecimal to binary conversion of (43) which is in decimal form, convert 4 and the 3 into 4 bits separately, and then combine the answer.
4 = 0100.
3 = 0011.
43 = 01000011.
4 = 0100.
3 = 0011.
43 = 01000011.
Shashi said:
8 years ago
In Hexa it is okay as (2B) but in Binary it will be (00101011).
If you go for direct conversion of 2 it will be 0010 & B will be 1011 so totally it would be 00101011.
If you go for direct conversion of 2 it will be 0010 & B will be 1011 so totally it would be 00101011.
Surekha said:
1 decade ago
Hex to decimal:
Divide 43 by 2 as shown:
43/2 = 21 rem 1 again divide 21 with 2.
21/2 = 10 rem 1.
10/2 = 5 rem 0.
5/2 = 2 rem 1.
2/2 = 1 rem 0.
00101011 = 2B.
Divide 43 by 2 as shown:
43/2 = 21 rem 1 again divide 21 with 2.
21/2 = 10 rem 1.
10/2 = 5 rem 0.
5/2 = 2 rem 1.
2/2 = 1 rem 0.
00101011 = 2B.
Sateesh said:
1 decade ago
One simple logic among answers is 43 is odd number. So always LSB is 1 and Hexadecimal also odd number should come as left nibble like (B).
Ravichinna said:
1 year ago
In hexa decimal 43= 2B,
And 43 in BCD presentation 4 = 0100, 3 = 0011.
43 = 01000011
So, the answer is 2B : 01000011.
And 43 in BCD presentation 4 = 0100, 3 = 0011.
43 = 01000011
So, the answer is 2B : 01000011.
Babu said:
8 years ago
Binary code BCD code both are different, in binary it is 00101011, but in BCD it is 0100 0011.
(2)
JEMSHIHAS said:
9 years ago
43/16.
Quotient = 2 in Decimal = 2 in Hex.
Remainder = 11 in Decimal = B in Hex.
Quotient = 2 in Decimal = 2 in Hex.
Remainder = 11 in Decimal = B in Hex.
(3)
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