Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 19)
19.
Decimal 43 in hexadecimal and BCD number system is respectively.
Answer: Option
Explanation:
(43)10 = (2B)16
(43)10 = (01000011)2 .
Discussion:
17 comments Page 1 of 2.
Pavan Dhanush said:
3 years ago
I think the answer should be (43)2 is 101011.
(4)
JEMSHIHAS said:
9 years ago
43/16.
Quotient = 2 in Decimal = 2 in Hex.
Remainder = 11 in Decimal = B in Hex.
Quotient = 2 in Decimal = 2 in Hex.
Remainder = 11 in Decimal = B in Hex.
(3)
Shiwangi said:
7 years ago
How 2B ? Can any one explain it?
(2)
Babu said:
8 years ago
Binary code BCD code both are different, in binary it is 00101011, but in BCD it is 0100 0011.
(2)
Lol said:
2 years ago
BCD is different from ordinary Binary.
(1)
Lemlem Aragaw said:
6 years ago
43/16 =2.
16*2 =32.
therefore 43-32 =11.
Then we will convert 43 to binary number.
43/2 = 21 rem 1 again divide 21 with 2.
21/2 = 10 rem 1.
10/2 = 5 rem 0.
5/2 = 2 rem 1.
2/2 = 1 rem 0.
0101011.
so A=10.
B=11.
And the answer will be 2B, 0101011.
16*2 =32.
therefore 43-32 =11.
Then we will convert 43 to binary number.
43/2 = 21 rem 1 again divide 21 with 2.
21/2 = 10 rem 1.
10/2 = 5 rem 0.
5/2 = 2 rem 1.
2/2 = 1 rem 0.
0101011.
so A=10.
B=11.
And the answer will be 2B, 0101011.
(1)
Rathi said:
1 decade ago
In a binary system all possible combinations of bits are valid.
In a BCD system there are 4 bits per digit. And the only valid combinations are 0(0000 Binary) through to 9(1001 Binary). If you want more digits then you have to add another 4-bit set.
So the number 43 would be represented by 101011 in binary and 0100 0011 in BCD.
In a BCD system there are 4 bits per digit. And the only valid combinations are 0(0000 Binary) through to 9(1001 Binary). If you want more digits then you have to add another 4-bit set.
So the number 43 would be represented by 101011 in binary and 0100 0011 in BCD.
(1)
Sasi said:
9 years ago
How 00101011? Please explain.
Ravichinna said:
1 year ago
In hexa decimal 43= 2B,
And 43 in BCD presentation 4 = 0100, 3 = 0011.
43 = 01000011
So, the answer is 2B : 01000011.
And 43 in BCD presentation 4 = 0100, 3 = 0011.
43 = 01000011
So, the answer is 2B : 01000011.
Nagaraj said:
7 years ago
In hexa the given decimal number should be divided by 16 (in 43 it has 2 as a quotient) and the remainder should be converted to direct Hexa equivalent number (in here it is 11 it's equivalent hexa number is B).
So, combining these we get {2B}.
So, combining these we get {2B}.
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