Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 1)
1.
The resolution of an n bit DAC with a maximum input of 5 V is 5 mV. The value of n is
Answer: Option
Explanation:
1000 = 5 or N = 10.
Discussion:
32 comments Page 3 of 4.
Chaithanya said:
7 years ago
Anyone know a shortcut to find the log values?
Aparna said:
7 years ago
Thanks @Sneha.
Karthickraja said:
7 years ago
5v is 5mv which means the 5v hv n number of 5mv so;
5v=n*5mv,
5v=10*5mv.
5v=n*5mv,
5v=10*5mv.
Priyadarshini said:
7 years ago
Thank you for the clear solution @Sneha.
(1)
Pallavi said:
7 years ago
Nice explanations, thanks All.
Dhana said:
5 years ago
Clear explanation. Thanks all.
(2)
Ashok said:
5 years ago
Thank you all for explaining.
(2)
Kavya said:
5 years ago
Thanks all for explaining the answer.
(2)
Palaniappan said:
5 years ago
Resolution =(vmax-vmin)/(2^N).
((2^N)-1) = (vmax-vmin/Resolution).
(2^N) = (5-0/5m)+1.
(2^N) = 1001.
Nx(log2) = (log (1001)).
N = (log (1001))/(log2).
N = 9.96.
((2^N)-1) = (vmax-vmin/Resolution).
(2^N) = (5-0/5m)+1.
(2^N) = 1001.
Nx(log2) = (log (1001)).
N = (log (1001))/(log2).
N = 9.96.
(9)
Biswas joy said:
3 years ago
Here, the Value of n = summation of total voltage.
(4)
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