Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 1)
1.
The resolution of an n bit DAC with a maximum input of 5 V is 5 mV. The value of n is
Answer: Option
Explanation:
1000 = 5 or N = 10.
Discussion:
32 comments Page 1 of 4.
Rakshatha priya P said:
2 years ago
Resolution = V/2^N-1.
5mV = 5/2^N-1
2^N-1 = 5/5*10^-3V
2^N-1 = 1/10^-3V
2^N-1 = 10^3V
2^N-1 = 1000
2^N = 1000+1
2^N = 1001.
The nearest power to this value for 2^N is 2^10.
i.e,2^9=512, 2^10=1024, then the value 1024 is nearest to 1001,
then 2^N=2^10,
=> N=10.
5mV = 5/2^N-1
2^N-1 = 5/5*10^-3V
2^N-1 = 1/10^-3V
2^N-1 = 10^3V
2^N-1 = 1000
2^N = 1000+1
2^N = 1001.
The nearest power to this value for 2^N is 2^10.
i.e,2^9=512, 2^10=1024, then the value 1024 is nearest to 1001,
then 2^N=2^10,
=> N=10.
(18)
Palaniappan said:
5 years ago
Resolution =(vmax-vmin)/(2^N).
((2^N)-1) = (vmax-vmin/Resolution).
(2^N) = (5-0/5m)+1.
(2^N) = 1001.
Nx(log2) = (log (1001)).
N = (log (1001))/(log2).
N = 9.96.
((2^N)-1) = (vmax-vmin/Resolution).
(2^N) = (5-0/5m)+1.
(2^N) = 1001.
Nx(log2) = (log (1001)).
N = (log (1001))/(log2).
N = 9.96.
(9)
Biswas joy said:
3 years ago
Here, the Value of n = summation of total voltage.
(4)
Nireesha S said:
12 months ago
Nice Explanations. Thanks all.
(3)
Kavya said:
5 years ago
Thanks all for explaining the answer.
(2)
Ashok said:
5 years ago
Thank you all for explaining.
(2)
Dhana said:
5 years ago
Clear explanation. Thanks all.
(2)
Priyadarshini said:
7 years ago
Thank you for the clear solution @Sneha.
(1)
Shamly said:
8 years ago
Resolution of DAC =[full scale range]/[(2^n)-1],
Given full scale range 5v.
Resolution of DAC =5mv.
So,
5 * 10^-3 = 5/(2^n-1).
You will get the answer.
Given full scale range 5v.
Resolution of DAC =5mv.
So,
5 * 10^-3 = 5/(2^n-1).
You will get the answer.
(1)
Manoj said:
8 years ago
iIf n^2 = 1001,
So n = 31.46.
So n = 31.46.
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