Electronics and Communication Engineering - Digital Electronics - Discussion

1. 

The resolution of an n bit DAC with a maximum input of 5 V is 5 mV. The value of n is

[A]. 8
[B]. 9
[C]. 10
[D]. 11

Answer: Option C

Explanation:

1000 = 5 or N = 10.


Sairam said: (Apr 1, 2014)  
Will you please give me a complete formula you have used?

Abi said: (May 9, 2014)  
2^n>(Vmax-Vmin)/ resolution.

Mukesh Kumar said: (Sep 21, 2014)  
What is DAC?

Niraj Gupta said: (Oct 2, 2014)  
DAC - Digital-to-Analog Converter.

Nethra said: (Dec 10, 2014)  
How is this simplified?

Priya said: (Jan 9, 2015)  
Any one give clear explanation?

Krishna said: (Jan 14, 2015)  
Resolution = Analog Input/Number of Steps.

Number of Steps = (2^N)-1.

Resolution = 5m.
Analog Input = 5.
N = 9.96 something.

In terms of resolution always round off to higher number. So 10.

Apurw said: (Jan 20, 2015)  
Resolution = v/2^n-1.

Bhuvana said: (Feb 20, 2015)  
I can't understand. Please give clear explanation.

Smarak Tripathy said: (Mar 8, 2015)  
Resolution = Analog Input/Number of Steps.

Number of Steps = (2^N)-1.

Resolution = 5 m.

Analog Input = 5.

N = 9.96 something.

In terms of resolution always round off to higher number. So 10 the simplified explanation.

Myvizhi said: (Sep 1, 2015)  
How can you say N = 9.96 something?

Raj said: (Feb 29, 2016)  
How 1000 you take for calculation?

Jr.R said: (Mar 5, 2016)  
Resolution: V/2^n -1.

In the problem resolution is given r=5mV(5x10^-3), and we're to find the n-bit.

By equating the formula of resolution:
We Let x=n as a variable of unknown.

5*10^-3=5/2^x -1 ---> input in your calculator then shift solve for X then press = you can get 9.967 or approximately equal to 10.

Sudheer said: (Dec 1, 2016)  
Resolution = Vr / 2^n -1.
5m = 5/2^n -1.
2^n -1 = 5/5m.
2^n-1 = 1000.
2^n = 1001.
So, n should be 10.

Shamly said: (Apr 17, 2017)  
Resolution of DAC =[full scale range]/[(2^n)-1],
Given full scale range 5v.
Resolution of DAC =5mv.

So,
5 * 10^-3 = 5/(2^n-1).
You will get the answer.

Venky said: (Jun 12, 2017)  
Please clarify to understand.

Sethu said: (Aug 20, 2017)  
Resolution = V / 2^n -1. (Given resolution=5*10^-3, V=5, n=?) substitute values to the equation.

5*10^-3= 5/2^n -1.
2^n -1 = 5/5*10^-3
2^n-1 = 5*10^3 /5
=10^3
=1000
2^n =1000+1
= 1001
2^n = 1001. (Take log on both sides)

nlog2 = log(1001)
n = log(1001)/ log2
= 9.96722 (round to 10) =10.

Manoj said: (Oct 15, 2017)  
iIf n^2 = 1001,
So n = 31.46.

Sneha .Khot said: (Nov 12, 2017)  
((2^N)-1) = (Input/Resolution ).
(2^N) = (5/5m)+1.
(2^N) = 1001.
Nx(log2) = (log (1001)).
N = (log (1001))/(log2).
N = 9.96.

Dhiru said: (Feb 20, 2018)  
Nice solution, Thanks @ Sneha.

Chaithanya said: (May 22, 2018)  
Anyone know a shortcut to find the log values?

Aparna said: (Jul 22, 2018)  
Thanks @Sneha.

Karthickraja said: (Jul 25, 2018)  
5v is 5mv which means the 5v hv n number of 5mv so;
5v=n*5mv,
5v=10*5mv.

Priyadarshini said: (Jul 30, 2018)  
Thank you for the clear solution @Sneha.

Pallavi said: (Nov 19, 2018)  
Nice explanations, thanks All.

Dhana said: (May 29, 2020)  
Clear explanation. Thanks all.

Ashok said: (Jul 6, 2020)  
Thank you all for explaining.

Kavya said: (Feb 13, 2021)  
Thanks all for explaining the answer.

Palaniappan said: (Feb 16, 2021)  
Resolution =(vmax-vmin)/(2^N).
((2^N)-1) = (vmax-vmin/Resolution).
(2^N) = (5-0/5m)+1.
(2^N) = 1001.
Nx(log2) = (log (1001)).
N = (log (1001))/(log2).
N = 9.96.

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