# Electronics and Communication Engineering - Digital Electronics - Discussion

1.

The resolution of an n bit DAC with a maximum input of 5 V is 5 mV. The value of n is

 [A]. 8 [B]. 9 [C]. 10 [D]. 11

Explanation: 1000 = 5 or N = 10.

 Sairam said: (Apr 1, 2014) Will you please give me a complete formula you have used?

 Abi said: (May 9, 2014) 2^n>(Vmax-Vmin)/ resolution.

 Mukesh Kumar said: (Sep 21, 2014) What is DAC?

 Niraj Gupta said: (Oct 2, 2014) DAC - Digital-to-Analog Converter.

 Nethra said: (Dec 10, 2014) How is this simplified?

 Priya said: (Jan 9, 2015) Any one give clear explanation?

 Krishna said: (Jan 14, 2015) Resolution = Analog Input/Number of Steps. Number of Steps = (2^N)-1. Resolution = 5m. Analog Input = 5. N = 9.96 something. In terms of resolution always round off to higher number. So 10.

 Apurw said: (Jan 20, 2015) Resolution = v/2^n-1.

 Bhuvana said: (Feb 20, 2015) I can't understand. Please give clear explanation.

 Smarak Tripathy said: (Mar 8, 2015) Resolution = Analog Input/Number of Steps. Number of Steps = (2^N)-1. Resolution = 5 m. Analog Input = 5. N = 9.96 something. In terms of resolution always round off to higher number. So 10 the simplified explanation.

 Myvizhi said: (Sep 1, 2015) How can you say N = 9.96 something?

 Raj said: (Feb 29, 2016) How 1000 you take for calculation?

 Jr.R said: (Mar 5, 2016) Resolution: V/2^n -1. In the problem resolution is given r=5mV(5x10^-3), and we're to find the n-bit. By equating the formula of resolution: We Let x=n as a variable of unknown. 5*10^-3=5/2^x -1 ---> input in your calculator then shift solve for X then press = you can get 9.967 or approximately equal to 10.

 Sudheer said: (Dec 1, 2016) Resolution = Vr / 2^n -1. 5m = 5/2^n -1. 2^n -1 = 5/5m. 2^n-1 = 1000. 2^n = 1001. So, n should be 10.

 Shamly said: (Apr 17, 2017) Resolution of DAC =[full scale range]/[(2^n)-1], Given full scale range 5v. Resolution of DAC =5mv. So, 5 * 10^-3 = 5/(2^n-1). You will get the answer.

 Venky said: (Jun 12, 2017) Please clarify to understand.

 Sethu said: (Aug 20, 2017) Resolution = V / 2^n -1. (Given resolution=5*10^-3, V=5, n=?) substitute values to the equation. 5*10^-3= 5/2^n -1. 2^n -1 = 5/5*10^-3 2^n-1 = 5*10^3 /5 =10^3 =1000 2^n =1000+1 = 1001 2^n = 1001. (Take log on both sides) nlog2 = log(1001) n = log(1001)/ log2 = 9.96722 (round to 10) =10.

 Manoj said: (Oct 15, 2017) iIf n^2 = 1001, So n = 31.46.

 Sneha .Khot said: (Nov 12, 2017) ((2^N)-1) = (Input/Resolution ). (2^N) = (5/5m)+1. (2^N) = 1001. Nx(log2) = (log (1001)). N = (log (1001))/(log2). N = 9.96.

 Dhiru said: (Feb 20, 2018) Nice solution, Thanks @ Sneha.

 Chaithanya said: (May 22, 2018) Anyone know a shortcut to find the log values?

 Aparna said: (Jul 22, 2018) Thanks @Sneha.

 Karthickraja said: (Jul 25, 2018) 5v is 5mv which means the 5v hv n number of 5mv so; 5v=n*5mv, 5v=10*5mv.

 Priyadarshini said: (Jul 30, 2018) Thank you for the clear solution @Sneha.

 Pallavi said: (Nov 19, 2018) Nice explanations, thanks All.

 Dhana said: (May 29, 2020) Clear explanation. Thanks all.

 Ashok said: (Jul 6, 2020) Thank you all for explaining.

 Kavya said: (Feb 13, 2021) Thanks all for explaining the answer.

 Palaniappan said: (Feb 16, 2021) Resolution =(vmax-vmin)/(2^N). ((2^N)-1) = (vmax-vmin/Resolution). (2^N) = (5-0/5m)+1. (2^N) = 1001. Nx(log2) = (log (1001)). N = (log (1001))/(log2). N = 9.96.