# Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 1 (Q.No. 1)

1.

The resolution of an

*n*bit DAC with a maximum input of 5 V is 5 mV. The value of*n*isAnswer: Option

Explanation:

1000 = 5 or N = 10.

Discussion:

32 comments Page 1 of 4.
Nireesha S said:
1 week ago

Nice Explanations. Thanks all.

Rakshatha priya P said:
1 year ago

Resolution = V/2^N-1.

5mV = 5/2^N-1

2^N-1 = 5/5*10^-3V

2^N-1 = 1/10^-3V

2^N-1 = 10^3V

2^N-1 = 1000

2^N = 1000+1

2^N = 1001.

The nearest power to this value for 2^N is 2^10.

i.e,2^9=512, 2^10=1024, then the value 1024 is nearest to 1001,

then 2^N=2^10,

=> N=10.

5mV = 5/2^N-1

2^N-1 = 5/5*10^-3V

2^N-1 = 1/10^-3V

2^N-1 = 10^3V

2^N-1 = 1000

2^N = 1000+1

2^N = 1001.

The nearest power to this value for 2^N is 2^10.

i.e,2^9=512, 2^10=1024, then the value 1024 is nearest to 1001,

then 2^N=2^10,

=> N=10.

(4)

Biswas joy said:
3 years ago

Here, the Value of n = summation of total voltage.

(2)

Palaniappan said:
4 years ago

Resolution =(vmax-vmin)/(2^N).

((2^N)-1) = (vmax-vmin/Resolution).

(2^N) = (5-0/5m)+1.

(2^N) = 1001.

Nx(log2) = (log (1001)).

N = (log (1001))/(log2).

N = 9.96.

((2^N)-1) = (vmax-vmin/Resolution).

(2^N) = (5-0/5m)+1.

(2^N) = 1001.

Nx(log2) = (log (1001)).

N = (log (1001))/(log2).

N = 9.96.

(7)

Kavya said:
4 years ago

Thanks all for explaining the answer.

(2)

Ashok said:
4 years ago

Thank you all for explaining.

(2)

Dhana said:
4 years ago

Clear explanation. Thanks all.

(2)

Pallavi said:
6 years ago

Nice explanations, thanks All.

Priyadarshini said:
6 years ago

Thank you for the clear solution @Sneha.

(1)

Karthickraja said:
6 years ago

5v is 5mv which means the 5v hv n number of 5mv so;

5v=n*5mv,

5v=10*5mv.

5v=n*5mv,

5v=10*5mv.

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers