Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 13)
13.
The circuit in the given figure is
Answer: Option
Explanation:
Since V(I) is lower state than V(0) it is a negative logic circuit. Since diodes are in reversed parallel, it is an AND gate.
Note: In Boolean algebra it is recognized that a positive logic OR is a negative logic AND. Similarly a positive logic AND is a negative logic OR.
Discussion:
29 comments Page 1 of 3.
Vicky said:
7 years ago
The actual configuration is for Positive logic (i,e logic 1= Vr and logic 0 = 0) AND gate, BUT since the logic has been changed to negative logic (i, e logic 1= 0, and logic 0= Vr), so instead of AND gate it will be OR gate. So, it is a Negative Logic OR gate.
(4)
Shiva said:
5 years ago
Not getting, Please Explain briefly.
(2)
TARUN UPADHYAY said:
5 years ago
It is -ve because 0 volts is shown as a logic high, and 1 volt is shown by logic low.
(2)
Ravi shankar kumar said:
1 decade ago
Since V (1) is lower state than V (0) it is a negative logic circuit. Here diode is not adding at the junction but away from the junction. So it is negative logic AND Gate.
(1)
Kanika Sharma said:
7 years ago
Please, clearly explain about positive and negative logic.
(1)
Kanika Sharma said:
7 years ago
If diodes are in series then what is the answer?
(1)
Priyadarshini said:
7 years ago
How OR gate? anyone explain me clearly.
(1)
Badhshah said:
8 years ago
That is the diodes are connected in the reverse direction that is for 0 it is ON for diode it is forward biased when negative pulse is applied.
(1)
Sai said:
8 years ago
How we find AND OR using diodes?
Ramya said:
7 years ago
This is negative logic or gate.
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