Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 9)
9.
BCD input 1000 is fed to a 7 segment display through a BCD to 7 segment decoder/driver. The segments which will lit up are
Answer: Option
Explanation:
1000 equals decimal 8 Therefore all segments will lit up.
Discussion:
14 comments Page 1 of 2.
Lakshmi sowjanya janga said:
1 decade ago
I need explanation any body please give me the explanation for this.
Gayathri said:
1 decade ago
How do we come to know that all segments will lit up? Anyone give correct explanation regarding this?
Sharanya Ram said:
1 decade ago
But the center g segment will not glow to denote 8.
PRAGYA SONI said:
1 decade ago
Please explain it.
Ruhi said:
10 years ago
g is not denoting 8 it is denoting 7.
Prarthi said:
9 years ago
BCD has 1000 input, so an output of the decoder is 11111111.
Niki said:
9 years ago
The segment are fixed.
S.MANJULADEVI said:
8 years ago
How do you say? @Prarthi.
(1)
Seema said:
8 years ago
Please, Explain in detail.
SUMITH RAYABHARAPU said:
8 years ago
As seven segment display has 8 LED's[a,b,c,d,e,f,g and a decimal point dp].... and is driven by BCD.
So the i/p's of this BCD will have the following result on seven segment display,
0000-no o/p
0001-a
0010-a,b
0011-a,b,c
0100-a,b,c,d
.....
.....
....
1000-a,b,c,d,e,f,g & dp.
i.e., all LED's are lit up.
So the i/p's of this BCD will have the following result on seven segment display,
0000-no o/p
0001-a
0010-a,b
0011-a,b,c
0100-a,b,c,d
.....
.....
....
1000-a,b,c,d,e,f,g & dp.
i.e., all LED's are lit up.
(3)
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