Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 3 (Q.No. 40)
40.
0.10112 = __________ .
Answer: Option
Explanation:
0.5 + 0 + 0.125 + 0.0625 = 0.6875.
Discussion:
3 comments Page 1 of 1.
Snehitha said:
6 years ago
0.1011 = 0*2^0.
1*2^-1 + 0*2^-2 +1*2^-3+1*2^-4 = 0.(0.5+0+0.125+0.0625),
= 0.6875.
1*2^-1 + 0*2^-2 +1*2^-3+1*2^-4 = 0.(0.5+0+0.125+0.0625),
= 0.6875.
Ashwini said:
6 years ago
Please explain the answer in detail.
Hema said:
7 years ago
I did not understand the solution. Can you explain clearly?
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