Electronics and Communication Engineering - Communication Systems
Exercise : Communication Systems - Section 4
- Communication Systems - Section 13
- Communication Systems - Section 25
- Communication Systems - Section 24
- Communication Systems - Section 23
- Communication Systems - Section 22
- Communication Systems - Section 21
- Communication Systems - Section 20
- Communication Systems - Section 19
- Communication Systems - Section 18
- Communication Systems - Section 17
- Communication Systems - Section 16
- Communication Systems - Section 15
- Communication Systems - Section 14
- Communication Systems - Section 1
- Communication Systems - Section 12
- Communication Systems - Section 11
- Communication Systems - Section 10
- Communication Systems - Section 9
- Communication Systems - Section 8
- Communication Systems - Section 7
- Communication Systems - Section 6
- Communication Systems - Section 5
- Communication Systems - Section 4
- Communication Systems - Section 3
- Communication Systems - Section 2
36.
Assertion (A): In standing wave pattern, the nodes and anti nodes are separated by half wave-length
Reason (R): When line is terminated in resistance RL, the standing wave ratio is SWR = Z0/RL or RL/Z0
Answer: Option
Explanation:
.
37.
An amplifier has an input resistance of 10 kΩ and the noise voltage is 10 μV. If two such resistances of 10 kΩ each are connected in series at the input, the total noise voltage is about
Answer: Option
Explanation:
Noise voltage = 10 = 14.14 μV.
38.
A 400 W carrier is modulated to a depth of 75 percent. The total power in modulated wave will be
Answer: Option
Explanation:
Pc = 400 W, m = 0.75
39.
In a colour TV receiver the bandwidth of RF amplifier is
Answer: Option
Explanation:
It is kept a little more than channel width so that reception is not restricted.
40.
An FM signal with a deviation is passes through the mixer, and has its frequency reduced five fold. The deviation in the output of the mixer is
Answer: Option
Explanation:
Δf (frequency deviation) is independent of fm , Δf depends only upon amplitude of message signal.
Δf = kf.Am .
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