# Electronics and Communication Engineering - Automatic Control Systems - Discussion

Discussion Forum : Automatic Control Systems - Section 1 (Q.No. 1)

1.

For the system in the given figure the characteristic equation is

Answer: Option

Explanation:

Transfer function = .

Hence characteristic equation is .

Discussion:

13 comments Page 1 of 2.
Adam said:
3 years ago

The characteristic equation is nothing more than setting the denominator of the closed-loop transfer function to zero (0).

According to this, option D is correct.

According to this, option D is correct.

(1)

Mufeed said:
6 years ago

For unity feedback systems the transfer function is G (S)/1+G (S).

So, the characteristic equation is 1+G (S) = 0.

So, the characteristic equation is 1+G (S) = 0.

SUJJI said:
9 years ago

For unity feedback systems the transfer function is G (S)/1+G (S).

So the characteristic equation is 1+G (S) = 0.

So the characteristic equation is 1+G (S) = 0.

Chanchal said:
7 years ago

@ALL.

As per the question, characteristics eq. 1+ G(s).H(s). Here H(s) is unity. So option A is right.

As per the question, characteristics eq. 1+ G(s).H(s). Here H(s) is unity. So option A is right.

Sagar kumar said:
8 years ago

This is helpful to improve the technical skills. Please provide more advance questions.

Navtej bhangu said:
8 years ago

Characteristic equation is given by 1 + G(S) H(S) = 0.

So, H(s) = 0.

So, H(s) = 0.

Ramya said:
9 years ago

Here characteristics equation is 1+G(s)H(s) = 0.

Abhishek said:
7 years ago

I think k(s+1) (s+3) =0 will be the answer.

VAIJINATH said:
3 years ago

Anyone, Please explain it fully & clearly.

SHAHWAZ said:
1 decade ago

Where is output and input of this system?

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