Electronics and Communication Engineering - Automatic Control Systems - Discussion
Discussion Forum : Automatic Control Systems - Section 1 (Q.No. 1)
1.
For the system in the given figure the characteristic equation is
K(s + 1)(s + 3) = 0
s(s + 2) = 0
Answer: Option
Explanation:
Transfer function = 
.
Hence characteristic equation is 
.
Discussion:
13 comments Page 1 of 2.
RISHI NIGAM said:
3 years ago
Here, we can use 1 + KG(S)H(S) = 0.
VAIJINATH said:
3 years ago
Anyone, Please explain it fully & clearly.
Adam said:
3 years ago
The characteristic equation is nothing more than setting the denominator of the closed-loop transfer function to zero (0).
According to this, option D is correct.
According to this, option D is correct.
(1)
Mufeed said:
5 years ago
For unity feedback systems the transfer function is G (S)/1+G (S).
So, the characteristic equation is 1+G (S) = 0.
So, the characteristic equation is 1+G (S) = 0.
Mufeed ardouno said:
5 years ago
Thank you all.
Chanchal said:
7 years ago
@ALL.
As per the question, characteristics eq. 1+ G(s).H(s). Here H(s) is unity. So option A is right.
As per the question, characteristics eq. 1+ G(s).H(s). Here H(s) is unity. So option A is right.
Abhishek said:
7 years ago
I think k(s+1) (s+3) =0 will be the answer.
Shristy said:
7 years ago
I think the H(s) is not 0 it is 1.
Sagar kumar said:
8 years ago
This is helpful to improve the technical skills. Please provide more advance questions.
Navtej bhangu said:
8 years ago
Characteristic equation is given by 1 + G(S) H(S) = 0.
So, H(s) = 0.
So, H(s) = 0.
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