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Electronics and Communication Engineering - Automatic Control Systems

Exercise : Automatic Control Systems - Section 3
16.
For the feedback system with closed loop transfer function the settling time for 2% tolerance
4ξωn
Answer: Option
Explanation:

and settling time for 2% tolerance is 4T.

17.
In a second order system with a unit step input, the speed of response is high if system is
overdamped
undamped system
critically damped
underdamped
Answer: Option
Explanation:

An underdamped system with damping factor slightly less than 1 gives high speed of response.

18.
A thermometer requires 1 minute to indicate 98% of its final response to a step input. If it is a first order system the time constant is
1 minute
0.5 minute
0.25 minute
0.1 minute
Answer: Option
Explanation:

0.98 = 1 - e-1/T or T = 0.25 minute.

19.

Assertion (A): A slight change in pole-zero configuration can cause only minor changes in root locus configuration.

Reason (R): Asymptotes show the behaviour of root loci for |s| >> 1

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is correct but R is wrong
R is correct but A is wrong
Answer: Option
Explanation:

Even a slight change in pole-zero position may affect root locus appreciably.

20.
In a second order system ωn = 10 rad/sec and ζ = 0.1, then ωd =
9.1 rad/sec
9.95 rad/sec
9 rad/sec
1 rad/sec
Answer: Option
Explanation:

Wd = ωn1 - ζ2 = 10 (1 - 0.01)05 = 9.95 rad/s.

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